Dmitri Pavlutin digs into why parseInt(0.0000005); evaluates to 5: parseInt(0.5); // => 0 parseInt(0.05); // => 0 parseInt(0.005); // => 0 parseInt(0.0005); // => 0 parseInt(0.00005); // => 0 parseInt(0.000005); // => 0 parseInt(0.0000005); // => 5 🤯 Solving a Mystery Behavior of parseInt() in JavaScript → On a related note, Yannick Clybouw recently hit …
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